안녕하세요.

앞에 cron 스크립트를 사용했는데 7일자가 넘어도 4월 24일자가
지워지질 않거든요?

total 32
drwxr-xr-x    2 root     root         4096 Apr 24 04:13 03-04-24
drwxr-xr-x    2 root     root         4096 Apr 25 04:14 03-04-25
drwxr-xr-x    2 root     root         4096 Apr 26 04:14 03-04-26
drwxr-xr-x    2 root     root         4096 Apr 27 04:14 03-04-27
drwxr-xr-x    2 root     root         4096 Apr 28 04:15 03-04-28
drwxr-xr-x    2 root     root         4096 Apr 29 04:14 03-04-29
drwxr-xr-x    2 root     root         4096 Apr 30 04:15 03-04-30
drwxr-xr-x    2 root     root         4096 May  1 04:14 03-05-01

아래는 스크립트 입니다.

#!/bin/bash

export Today="`date '+%y-%m-%d'`"
LOGdir="/usr/local/apache/logs"

#cd /backup/data
#rm -f *.tar.gz

backup_dir="/backup/data"
mkdir -p ${backup_dir}/$Today

tar cfpz ${backup_dir}/${Today}/$Today-usr.local.mysql.tar.gz /usr/local/mysql
tar cfpz ${backup_dir}/${Today}/$Today-usr.local.apache.tar.gz /usr/local/apache
tar cfpz ${backup_dir}/${Today}/$Today-home.tar.gz /home
tar cfpz ${backup_dir}/${Today}/$Today-etc.tar.gz /etc

rm -f ${LOGdir}/*_log
/usr/bin/killall -HUP httpd


dirlists=`/bin/ls -t $backup_dir 2>/dev/null`

i=1
for dir in $dirlists ; do
  if [ "$i" -gt 7 ] ; then
    rm -rf $dir
  fi
  i=$(($i+1))
done

exit 0

뭐가 문제...